Topic: Q, Kc & Kp Conceptual problem. (Read 2930 times)

[V] · « **on:** November 06, 2010, 01:22:17 AM »

I am given

$\Delta H^{\circ} /$ &

$\Delta S^{\circ} /$ , and Temp (K)

I need to calculate

$K_{p} /$ at the given Temp (K).
I can solve for

$\Delta G^{\circ} /$
then use this this equation:

$\Delta G = \Delta G^{\circ} + RTlnQ /$

I just set

$\Delta G=0 /$ & solve for "Q".

My question is, will this Q value =

$K_{p} /$ or

$K_{c} /$ ?

rabolisk · « **Reply #1 on:** November 06, 2010, 01:34:41 PM »

There is a conversion between

and

[V] · « **Reply #2 on:** November 06, 2010, 01:58:46 PM »

Thank you.

I'm reading several different sources, some claim its kc some say its kp.

can you please explain why it is kc?