Hi,
I have done some research on Iodine because I am trying to design a chemistry game, and I have some questions about this substance.
(melting point: 386.85 K, 113.7 °C, 236.66 °F
Boiling point: 457.4 K, 184.3 °C, 363.7 °F)
I understand that many people think that iodine sublimes to gas without going through the liquid phase. I read that this is not completely true. Partly is sublimes, but partly it does become a liquid. But because of the dark purple vapor (that indeed sublimed) it is often not seen. This sounds logical to me because when you look at the triple point of iodine, it seems impossible to go from solid to liquid without passing the liquid phase (that is, under normal pressure of 1atm).
http://cwx.prenhall.com/petrucci/medialib/media_portfolio/text_images/FG13_18.JPGStill I wonder, when looking at this picture, how come it sublimes? for CO2 for instance it is easy to understand.
http://cwx.prenhall.com/petrucci/medialib/media_portfolio/text_images/FG13_19.JPGIf you heat solid iodine just below its melting point, and you wait long enough, will all the iodine sublimes without going through the liquid phase? Or is it not possible to sublime everything because you are still below the melting point and thus part of vapor will deposit back to solid crystals again.
So what I would actually like to know is, at normal temperature, and normal pressure, when exactly will iodine start to sublime? And, the other way around, when you have heated iodine gas, at what temperature exactly will it start to deposit back again to solid. (when it is just below the the melting point? I assume that solid iodine does not exist above melting point?)
Furthermore if you would heat or cool iodine until exactly 150 degrees Celsius, will iodine only exist in the liquid phase, like you would expect, or in multiple phases. (since iodine behaves so weird anyway
Thanks for helping me!