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Topic: O Chemistry problem  (Read 3136 times)

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Offline wstmar1

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O Chemistry problem
« on: November 30, 2010, 11:34:14 PM »
2-methylbutene   (reacting in the presence of H2SO4)   -->  2-methylbut-1-ol


What does the mechanism for this look like?
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Offline MissPhosgene

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Re: O Chemistry problem
« Reply #1 on: December 01, 2010, 12:29:37 AM »
The place to start is figuring out where the alkene will get protonated. You can do that by thinking about forming the most stable carbocation.
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Stereograms of the 32 crystallographic point groups: little bike wheels of cold, hard, pure rationality.

Offline OC pro

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Re: O Chemistry problem
« Reply #2 on: December 01, 2010, 04:10:56 PM »
Quote from: wstmar1 on November 30, 2010, 11:34:14 PM
2-methylbutene   -->  2-methylbut-1-ol

Educt is not properly named (position of double bond has to be specified). Name of product is also wrong spelled.
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cupid.callin

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Re: O Chemistry problem
« Reply #3 on: December 02, 2010, 04:29:25 PM »
Yeah ... It should be 2-methylbutan-2-ol

first bond shifts...then H+ attacks negative charge ... then lone pair of O from H20  attacks  + charge and then H+ leaves from H2O.

But yeild of this reaction would be very less.
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