Hello, i've been going through some questions and i am stuck with this
What is the solubility product of silver chromate, Ag
2CrO
4, give that its solubility is 8.43x10
-5 mol dm
-3.
My steps are,
K
sp=
(Ag
+)
2(CrO
42-) =
(8.43x10
-5)
3 =
5.99 x 10
-13 mol
3dm
-9But the printed answer is 2.4x10
-12 mol
3dm
-9What did I do wrong? Please advise.