November 13, 2024, 02:08:24 AM
Forum Rules: Read This Before Posting


Topic: formula for a hydrate  (Read 3797 times)

0 Members and 1 Guest are viewing this topic.

afchick7689

  • Guest
formula for a hydrate
« on: September 07, 2005, 09:10:18 PM »
The problem reads:

A 1.0 g sample of the hydrate COSO4 x H2O gave on heating, 0.55 g of the anydrous salt, cobalt II sulfate.  What is the formula for the hydrate?

And my work is below-- i just had to teach myself the process for this one, so i wanted to make sure there weren't any errors I overlooked...

(CoSO4)x ? (H2O)y
Molar mass of hydrate: 58.933 + 32.065 + (16*4) = 154.998
Molar mass of water: 1.01*2 + 16 = 18.02
mass of hydrate used: 1.0g
mass of anhydrous salt left behind: 0.55g
mass of water left behind: 1.0 g - 0.55 g = 0.45g
moles of anhydrous salt present in hydrate: 0.55g/ 154.998g/mol = 0.0035484 mol
moles of water present in hydrate: 0.45g/ 18.02g/mol = 0.024972 mol
((Divide by smallest mole (0.0035484):
salt: 0.0035484 mol / 0.0035484 mol = 1
water: 0.024972 mol / 0.0035484 mol = 7.037 = 7
(CoSO4) ? (H2O)7

-thanks!!

Offline xiankai

  • Chemist
  • Full Member
  • *
  • Posts: 785
  • Mole Snacks: +77/-37
  • Gender: Male
Re:formula for a hydrate
« Reply #1 on: September 08, 2005, 12:28:18 AM »
nothing wrong as far as i can see :)

u dont have to put the compound in brackets, though. also, put the molar fraction in front of the compound, so it reads something like CoSO4.7H2O
one learns best by teaching

Sponsored Links