A solution may contain NaOH, Na2CO3, NaHCO3 individually or as any pair of the three analytes. A 25.00 mL aliquot of the solution is treated with a standard solution of HCl. Given the following information, what analyte(s) are present in the solution? Addition of phenolphthalein indicator (pink at pH = 10.0 and colorless at pH = 8.3) to the solution gives a pink color. The solution becomes colorless after the methyl purple indicator (green at pH = 5.4 and purple at pH = 4.8 ) to this solution gives a green color. Addition of an additional 15.30 mL of 0.1000 M HCl causes the solution to become purple in color.
A) NaOH + NaCO3
B) NaCO3 + NaHCO3
C) NaHCO3
D) NaOH
Sorry I know that it isn't great grammar and that one of the sentences in there seems like its missing a few words, but I typed it up word for word, so what it's actually supposed to be, I don't know.
As for how to do this problem, I can tell that the original solution is basic since adding phenolphthalein produces a pink color, but assuming that it meant that the solution becomes colorless after the methyl purple indicator is added to this solution, I don't understand how that happens?