[dars]

You want to heat 1 L of water by 10 ºC so you heat it with a mechanical egg beater that is powered by a 1kg mass on a rope over a pulley. How far does the mass have to descend to supply enough work for heating the water?
Heres what I know:
delta T = 10degC
delta C = delta Q / delta T
Work in gravity is: integ x_f / x_i (mg)dx

I dont understand how to get the work. If i knew delta U then I could use U = q+w. So i am stuck as to where to start. Please help me get started..thanks

[Enthalpy]

You need the heat capacity of water. Having found it, you can learn it, since it serves.
Not important here: 1L water weighs 1kg at +4°C only.

Work can be converted into heat completely, and often is.

You will get a big height. Which explains why rivers arrive cool in the oceans, hi old Kelvin.

[dars]

So if heat is converted to work, then Q = w and Q is C*delta T = 753.0J = w

then integ x_f / x_i (mg)dx = 753J

mg(x_f - x_i) = 753J
(1kg)(9.81m/s/s) ( 0m - x_im) = 753J

x_i = 76.76m
Is that right? (it doesnt seem correct?)

[Enthalpy]

No.

Do you use a computation software for one product and two divisions?