[ch3mgirl]

Question is: How many molecules of carbon dioxide are formed when 10.0 grams of calcium carbonate are dissolved in an excess of hydrochloric acid solution?

I'm not sure how to begin to solve this problem.

So if I balance the equation, I get:

CaCO₃ (s) + 2 HCl (aq)   CO₂ (g) + H₂O (l) + CaCl₂ (aq)

Do I now calculate the number of moles in CaCO₃?

[DevaDevil]

yes indeed, calculate the moles of calcium carbonate first, then continue.. let us know where you get stuck

[ch3mgirl]

yes indeed, calculate the moles of calcium carbonate first, then continue.. let us know where you get stuck

Excellent, thank you.

When I calculate the number of moles in CaCO₃ I get 0.1 mol.
So if moles of CaCO₃=moles of CO₂ then I can calculate molecules and get 6.02 x 10²³ molecules of CO₂. Is this correct?

[DevaDevil]

number of molecules = number of moles * avogadro's number

so indeed you have 0.100 mol CaCO₃, and from stoechiometry it shows you have indeed 0.100 mol of CO₂, but the number of molecules is not correct yet..

[ch3mgirl]

number of molecules = number of moles * avogadro's number

so indeed you have 0.100 mol CaCO₃, and from stoechiometry it shows you have indeed 0.100 mol of CO₂, but the number of molecules is not correct yet..

Ahh, I mistyped... 6.02 X 10²² molecules of CO₂

[DevaDevil]

excellent

[ch3mgirl]

excellent

Thank you so much!