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Topic: Manganese Dioxide & Potassium Iodide  (Read 7169 times)

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Offline flyer517

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Manganese Dioxide & Potassium Iodide
« on: February 14, 2011, 11:41:56 PM »
Hi All

I was hoping someone could tell me if I am on the right track with an assignment question.  It is fairly long question but I am just unsure about the first part which is the equation for the reaction of Manganese Dioxide with Potassium Iodide.  This is what I think happens:

MnO2 + 2KI  :rarrow: MnI2 + K2O2

Is this correct?

Many thanks.

Flyer

PS:  Sorry, updated my post title to be more appropriate.

Offline Nobby

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Re: Manganese Dioxide & Potassium Iodide
« Reply #1 on: February 15, 2011, 06:58:24 AM »
Question is schould it takes place in aquaeous solution or bei melting.

Inaquaeus soution:

MnO2 + 2 H2O + 2 I- => Mn2+ + 4 OH- + I2

If melted I suppose a kind of Manganate-IV or -III will be formed. But never Potassium peroxide.


Offline DevaDevil

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Re: Manganese Dioxide & Potassium Iodide
« Reply #2 on: February 15, 2011, 02:27:18 PM »
well, you should in case of redox reactions with inorganic chemicals always try to create half-cell reactions, and maybe check your tables of reduction potentials to see what would be likely to be created.

In your case treat the MnO2 (which will be reduced) separately from the KI (or I- in aqueous solution), which will be oxidised.

Make half-cell reactions and you can figure our the products

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