[Dubs]

Hello, im practicing molarity questions.
Question : "what is the molarity of each ion present by dissolving 15.0g of the following compound in water to make 655 ml of solution"

1) scandium (111) iodide

Well my first thought was to find out the molarity of the solution it:
Sc = 44.9
I   = 126.91 X 3 = 380.73
total mass = 425.69

(15.0 / 655ml)(1000ml / 1L)(1m of ScI / 425.69) = 0.0538 M of ScI
I dont know how to get from here to each ion's molarity.  Book says Sc = 0.0538 M and I = 0.161 M,
i dont understand how. even if i do the
I⁺ = (0.0538 M of ScI / 1 L)(3 mols of I ions/1 mol of ScI)
i still dont get the answer the book says is right. Am i just setting up the equations wrong?

[rabolisk]

Iodine is I^-, and 3 times 0.0538 = 0.161...

[Borek]

1) scandium (111) iodide

It is scandium(III) iodide. III as roman numeral 3, not as 111.