Can someone double check my work
?
Info:
Equivalence point at
29.38mL of .0506
M HCl
35.00mL of Ca(OH)
2First I have to find Concentration of OH
-(.0506
M)(.02938 L) = 1.49E-3 mols of HCl
because 1.49E-3 mols of H
+ ion we added to react with OH
-, we can say mols of HCl = mols of OH
-(1.49E-3 mols of OH
-)/(.035L) = .0425
M OH
-Is that correct ? ^^^ I know how to do Ksp if that is correct