Dear All,
I am facing a major problem for a simple amide coupling.
One side: The "amine" (1).
I have a R-NH3+Cl- that is only soluble in water.
The other side: The "acid" (2).
I have a methyl ester. I deprotect using LiOH in water:THF (1:1). The anionic form is soluble in water, MeOH, etc. As soon as I acidify the carboxylate it precipitates and the acid not soluble at all in any solvent (even not suspension in DMSO, DMF, mixture, etc...)
How would you perfom the amide coupling ?
Can we perform amide using the carboxylate form instead of the acid form ?
How "basifying" the protonated amine (1) ?
Thank you for your help
Jeanno