Nicotine, C10H14N2, has two basic nitrogen atoms and both can react with water.
Nic + H2O ---> NicH+ + OH-
NicH+ + H2O ---> NicH2 2+ + OH-
Kb1 = 7.0 x 10^-7
Kb2 = 1.1 x 10^-10
Calculate the pH of a 0.020 M solution.
I did it by only using the first equation and Kb1. How do you include Kb2 or do you not have to?