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Topic: Chemical Equilibrium Kc question  (Read 2480 times)

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Offline Dallon

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Chemical Equilibrium Kc question
« on: June 04, 2011, 03:25:51 PM »
This might seem a little rediculous to some but I simply can't do this question. Im in Chem 111 (part 2) -first year chem distance ed course and the textbook that was made by this guy is useless in helping me.

The question is:
For the reaction
 H2(g)+CO2(g) ::equil::CO(g)+H2O(g)

Kc=0.771 at 750 degrees C. Find the resulting concentrations of the H2 and H2O gases when 1.00 mol of H2 and 1.00 Mol of CO2 are placed in a 5.00 L container and permitted to reach equilibrium.
(How do I find these concentrations when there are 2 unknown variables)???

Also if someone could suggest a good place to get a full overview on barely soluble ionic solids and Fractional Precipitation reactions that'd be great. I'm learning this course basically from youtube and it only goes so far.

Offline Borek

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Re: Chemical Equilibrium Kc question
« Reply #1 on: June 04, 2011, 04:07:05 PM »
These two unknowns are related by the reaction stoichiometry.

How many moles of H2O are produced per each mole of CO?
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Offline Dallon

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Re: Chemical Equilibrium Kc question
« Reply #2 on: June 04, 2011, 06:22:32 PM »
One- They're both 1 to 1 moles- I actually did the equation by using the ICE table and got an annsweer but i dont know if it is right- Here's what I did- ( if i did it right ill know what to do for the next one).

  H2    +                     CO2 ::equil::                           CO+              H2O
I   (0.2M)                     (0.2M)                      (nothing)   (nothing)

C     -X                         -X                               +X            +X

E    (0.2-x)                  (0.2 -x)                            X              X



and then with this info i got


Kc(which is 0.771)= (X)2/ (0.2-X)2

which i got to be Sqrt 0.771 = X/( 0.2-X)
and the Sqrt of 0.771 = 0.878

0.878*(0.2-X)=(1.765X10-1-0.878X)
which is equal to X2

X=9.35X10-2

and therefore CO and H2O equal 9.35X10-2


did i get this right? or where did i go wrong

Offline Borek

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Re: Chemical Equilibrium Kc question
« Reply #3 on: June 05, 2011, 05:10:48 AM »
Looks OK to me. I didn't check the numbers, just the approach.
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