[BarcaBoy10]

I was wondering how to go about solving this particular question:

For mercury the enthalpy of vaporization is 58.51 kJ/mol and the entropy of vaporization is 92.92 J K^-1 mol^-1.

What is the normal boiling point of mercury?
Is the free energy  for vaporization positive or negative below the boiling point?

I have no clue how to even start this one. Something to do with  :delta:(G) =  :delta:(H) - T :delta:(S) maybe?

[Jorriss]

The important thing is, what is the free energy AT the normal boiling point?