December 23, 2024, 01:37:38 PM
Forum Rules: Read This Before Posting


« previous next »
Pages: [1]   Go Down

Topic: Stoichiometry  (Read 6748 times)

0 Members and 1 Guest are viewing this topic.

Offline devvaibhav

  • Regular Member
  • ***
  • Posts: 20
  • Mole Snacks: +0/-0
Stoichiometry
« on: June 08, 2011, 10:35:31 AM »
Q:- One mole of a mixture of CO and CO2 requires exactly 20 grams of NaOH to convert all the CO2 into Na2CO3. How many more grams of NaOH would it require for conversions into Na2CO3 if the mixture (one mole) is completely oxidized to CO2?

I am not able to solve it..Plz can anyone assist me with this??
Logged

Offline sjb

  • Global Moderator
  • Sr. Member
  • ***
  • Posts: 3653
  • Mole Snacks: +222/-42
  • Gender: Male
Re: Stoichiometry
« Reply #1 on: June 08, 2011, 10:43:39 AM »
Quote from: devvaibhav on June 08, 2011, 10:35:31 AM
Q:- One mole of a mixture of CO and CO2 requires exactly 20 grams of NaOH to convert all the CO2 into Na2CO3. How many more grams of NaOH would it require for conversions into Na2CO3 if the mixture (one mole) is completely oxidized to CO2?

I am not able to solve it..Plz can anyone assist me with this??

Can you write an equation representing the formation of sodium carbonate from carbon dioxide?
Logged

Offline devvaibhav

  • Regular Member
  • ***
  • Posts: 20
  • Mole Snacks: +0/-0
Re: Stoichiometry
« Reply #2 on: June 08, 2011, 10:56:50 AM »
Quote from: sjb on June 08, 2011, 10:43:39 AM
Quote from: devvaibhav on June 08, 2011, 10:35:31 AM
Q:- One mole of a mixture of CO and CO2 requires exactly 20 grams of NaOH to convert all the CO2 into Na2CO3. How many more grams of NaOH would it require for conversions into Na2CO3 if the mixture (one mole) is completely oxidized to CO2?

I am not able to solve it..Plz can anyone assist me with this??

Can you write an equation representing the formation of sodium carbonate from carbon dioxide?

This equation was told by our teacher. I wasnt able to understand it and i am going to ask it again to him on another class. ok here it is::Sorry this is not proper...(may be)

CO + CO2 (1 mole and assume that CO is not reacting)

CO2 + 2NaOH
Na2CO3 + H2O

I am quite unsure about it but it is the same which my teacher told....There is no reaction Given...So...any ideas.. plz reply...
Logged

Offline vmelkon

  • Chemist
  • Full Member
  • *
  • Posts: 474
  • Mole Snacks: +28/-10
  • Gender: Male
Re: Stoichiometry
« Reply #3 on: June 08, 2011, 05:31:59 PM »
How many moles is 20 g NaOH?
That number will tell you how many moles of CO2 was used. It will probably be less than 1 mole.
You'll then know how much CO you have (in moles).
etc.

Logged

Offline tanu

  • New Member
  • **
  • Posts: 5
  • Mole Snacks: +1/-0
Re: Stoichiometry
« Reply #4 on: June 09, 2011, 02:29:49 AM »
Is the ans. 60....
Logged

Offline Nobby

  • Full Member
  • ****
  • Posts: 167
  • Mole Snacks: +12/-16
  • Gender: Male
  • Vena lausa moris pax drux bis totis
Re: Stoichiometry
« Reply #5 on: June 09, 2011, 03:29:40 AM »
No.

The reaction need 20 g NaOH, that is 0,5 mol. This react with CO2, what means 0,25 mol. 2 NaOH fit with 1 CO2

The mixture was 1 mol CO and CO2 what means 0,75 mol CO is left. If we burn this as well then we have 0,75 mol CO2 and this requires 1,5 mol NaOH. In sum then 2 mol.
Logged

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27887
  • Mole Snacks: +1815/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Stoichiometry
« Reply #6 on: June 09, 2011, 04:59:36 AM »
Quote from: tanu on June 09, 2011, 02:29:49 AM
Is the ans. 60....

Yes.

Nobby: reread the question. You are close.
Logged
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline Nobby

  • Full Member
  • ****
  • Posts: 167
  • Mole Snacks: +12/-16
  • Gender: Male
  • Vena lausa moris pax drux bis totis
Re: Stoichiometry
« Reply #7 on: June 09, 2011, 05:32:32 AM »
Yes, well if somebody had written the unit then it is clear. 60 grams more is right.
Logged

Offline DrCMS

  • Chemist
  • Sr. Member
  • *
  • Posts: 1306
  • Mole Snacks: +212/-84
  • Gender: Male
Re: Stoichiometry
« Reply #8 on: June 09, 2011, 06:26:57 AM »
Quote from: Nobby on June 09, 2011, 05:32:32 AM
Yes, well if somebody had written the unit then it is clear. 60 grams more is right.

The question does not ask for the units it gives them as grams so the correct answer is 60 with no units.
Logged

Offline Nobby

  • Full Member
  • ****
  • Posts: 167
  • Mole Snacks: +12/-16
  • Gender: Male
  • Vena lausa moris pax drux bis totis
Re: Stoichiometry
« Reply #9 on: June 09, 2011, 06:32:42 AM »
Disagree!!

Quote
How many more grams of NaOH would it require for conversions into Na2CO3 if the mixture (one mole) is completely oxidized to CO2?

It asked for the grams. And generally in scientific calculation units are used.
Logged

Offline devvaibhav

  • Regular Member
  • ***
  • Posts: 20
  • Mole Snacks: +0/-0
Re: Stoichiometry
« Reply #10 on: June 09, 2011, 10:59:41 AM »
Quote from: tanu on June 09, 2011, 02:29:49 AM
Is the ans. 60....

yes the answer is 60 g...plz can u tell me how u got it??///
Logged

Offline Nobby

  • Full Member
  • ****
  • Posts: 167
  • Mole Snacks: +12/-16
  • Gender: Male
  • Vena lausa moris pax drux bis totis
Re: Stoichiometry
« Reply #11 on: June 09, 2011, 12:08:34 PM »
Check Post 5. You will find the result of 1.5 mol NaOH and this is 60 gram.
Logged

Offline DrCMS

  • Chemist
  • Sr. Member
  • *
  • Posts: 1306
  • Mole Snacks: +212/-84
  • Gender: Male
Re: Stoichiometry
« Reply #12 on: June 09, 2011, 04:45:12 PM »
Quote from: Nobby on June 09, 2011, 06:32:42 AM
Disagree!!

Quote
How many more grams of NaOH would it require for conversions into Na2CO3 if the mixture (one mole) is completely oxidized to CO2?

It asked for the grams. And generally in scientific calculation units are used.

You can disagree all you want but the fact is YOU got it wrong by misreading the question and then tried to justify it by making up rubbish about units.

As the question said "How many more grams of NaOH would it require ." the answer is 60.
If the question had said "what extra weight of NaOH would it require ." the answer would be 60 grams but that was not the question asked.
Logged
Pages: [1]   Go Up
« previous next »
Sponsored Links