[jscaryn]

Take nitrogen to be a Van de Waals gas with a=1.352 dm6 atm mol-2 and b= 0.0387dm3mol-1 , and calculate ∆Hm when the pressure on the gas decreased from 500atm to 1.00atm at 300K. For a Van der Waals gas, µ = {(2a/RT)-b}/Cp.m  . Assume Cp.m = 7/2 R.

The way that I am doing is:
dH = -µCp.m
∆H = ∫ dH
      = ∫ -µCp.m
µ = {(2a/RT)-b}/Cp.m
so, ∆H = ∫ (2a/RT)-b
That’s all I knowT_T

Can anyone help me pleaseT_T
is my equation correct?
why P is not inT_T
I will really appreciate if you help meT_T
ThanksT_T