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Topic: Help- Concentration problem.  (Read 5018 times)

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magicman

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Help- Concentration problem.
« on: September 26, 2005, 08:36:52 PM »
In the preparation of a solution of sulfuric acid, 23.100g of SO3 was dissolved in enough water to prepare 1.300L of solution. What is the concentration of sulfur (moles per liter) in this solution?



SO3 + H20 --------> H2SO4

The equation is already balanced.

So far this is what ive got in my work, but i fear im making a mistake somewhere.

23.100 g H2SO4|  1 mol H2SO4  |1 mol S           | 1 g S
                         98.02g H2SO4 | 1 mol H2 SO 4 |

           

I know i should of used the liters by now, but i dont know where to use it.... Thanks in advance for the help.

Offline mike

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Re:Help- Concentration problem.
« Reply #1 on: September 26, 2005, 08:50:07 PM »
m = 23.100g

M = 80 g.mol-1

v = 1.300L

n = m/M = 23.100/80 = 0.289 moles of SO3/H2SO4/S


c = n/v = 0.289/1.300 = 0.222 mol.L-1

does this seem right?
There is no science without fancy, and no art without facts.

magicman

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Re:Help- Concentration problem.
« Reply #2 on: September 26, 2005, 08:52:38 PM »
i wouldnt know...what was your final answer ? how much Sulfurer?

magicman

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Re:Help- Concentration problem.
« Reply #3 on: September 26, 2005, 08:54:35 PM »
actually i did. i see what u did, the calculations are right so i would assume yes your right thans.

Offline mike

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Re:Help- Concentration problem.
« Reply #4 on: September 26, 2005, 08:55:05 PM »
0.222mol.L-1 :-\
There is no science without fancy, and no art without facts.

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