[Timothy]

I am doing a question on expansion coefficients in physical chemistry. I have been given in the question,
V = V'{0.77 + 3.7*10-4(T/K) + 1.52*10^-6(T/K)^2} . This information has obviously been given for dV, my question is how do I interpret this. My thoughts are,

0.77 + 3.7*10-4 = 0.77037

0.77037 + 1.52*10^-6 = 0.77037152

So dV = 0.77037152 - 0.77
         = 0.00037152

[Schrödinger]

V = V'{0.77 + 3.7*10-4(T/K) + 1.52*10^-6(T/K)^2} .

To put this in a clearer way : V = V'{0.77 + T*3.7*10^-4 + T²*1.52*10^-6}

The new volume depends on two powers of T(in Kelvin), as the equation states.

0.77037 + 1.52*10^-6 = 0.77037152

So dV = 0.77037152 - 0.77
         = 0.00037152

Since no other data on temperature has been given, I am kind of confused at the above equations... You cannot use the relation between V and V' unless you know the temperature

Assuming that V' is the new volume and V is the old volume, remember that dV = V'-V
So,
1. If temperature is given, all you need to do is substitute it in the equation to get V' in terms of V
2. If temperature is not given, it is possible that you are asked to find dV in terms of T, which is basically some algebraic manipulations with the main equation...