[heyheyhey701]

Boyles law - V=k(1/P)
Charles law - V=k' (t+t0)

Determine the value of k and k' from the experimentally determined equations found earlier:
1) V = 26.7 (1/P) - 3.50 (find k)
2) Log V = 1.14 (log P) + 1.32 (find k)
3) V = .07t + 22.8 (find k')

[DevaDevil]

your attempt at solving this?

[Vidya]

Boyles law - V=k(1/P)
Charles law - V=k' (t+t0)

Determine the value of k and k' from the experimentally determined equations found earlier:
1) V = 26.7 (1/P) - 3.50 (find k)
2) Log V = 1.14 (log P) + 1.32 (find k)
3) V = .07t + 22.8 (find k')

what is K here ?
if you plot V vs 1/P then you should get a straight line.slope of that straight line is k
y = mx+b
compare this equation  
V = 26.7 (1/P) - 3.50 (find k)
m is the slope of the line and m is equal to 26.7
I hope now you can solve it