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Topic: Equilibrium - 4 questions  (Read 4210 times)

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Offline cho_reunited

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Equilibrium - 4 questions
« on: October 09, 2011, 01:02:00 PM »
1) Gas X2 reacts with gas Y2 to give gaseous XY according to this equation:
X2 + Y2 <=> 2XY
The equilibrium constant for the reaction is found to be 2.6 x 10-3
What will be the value of Keq for the reverse reaction?

The answer is 3.8 x 102
but I have no clue how they got that.



2) The equilibrium constant for the reaction A + B <=> C + D is 7.0 x 105
At a non-equilibrium situation, [A] = 0.4M, the molarity of B = 0.4M, [C] = 0.8M, [D] = 0.2M
Assuming sufficient activation energy, why does the would the reaction shift to the right (products) ?

Offline cho_reunited

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Re: Equilibrium - 4 questions
« Reply #1 on: October 09, 2011, 01:07:47 PM »
3) When initial concentrations of SO2 = 1.62M and 02 = 0.82M are heated, an equilibrium is established in which [SO3] = 1.22M.
If the equation is 2SO2 (g) + O2 (g) <=> 2SO3 (g) then what will be the value of Keq?

the answer is 44 but I haven't the foggiest how to get that.

Offline cho_reunited

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Re: Equilibrium - 4 questions
« Reply #2 on: October 09, 2011, 01:10:30 PM »
4)   The thermal dissociation of calcium carbonate is as follows:
CaCO3 (s) + heat <=> CaO (s) + CO2 (g)
In describing the compositions of different equilibrium mixtures produced at the same temperature by the above reaction, it is correct to say that all compositions have the same partial pressure of CO2
^^why is this?

Offline sjb

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Re: Equilibrium - 4 questions
« Reply #3 on: October 09, 2011, 03:43:50 PM »
1) Gas X2 reacts with gas Y2 to give gaseous XY according to this equation:
X2 + Y2 <=> 2XY
The equilibrium constant for the reaction is found to be 2.6 x 10-3
What will be the value of Keq for the reverse reaction?

The answer is 3.8 x 102
but I have no clue how they got that.

What is the expression for the equilibrium constant for the forward, and reverse reactions?


2) The equilibrium constant for the reaction A + B <=> C + D is 7.0 x 105
At a non-equilibrium situation, [A] = 0.4M, the molarity of B = 0.4M, [C] = 0.8M, [D] = 0.2M
Assuming sufficient activation energy, why does the would the reaction shift to the right (products) ?

What is the expression for the equilibrium constant?

Offline cho_reunited

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Re: Equilibrium - 4 questions
« Reply #4 on: October 09, 2011, 04:07:14 PM »
I don't know, that information isn't given to me.

Offline Borek

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Re: Equilibrium - 4 questions
« Reply #5 on: October 09, 2011, 05:32:12 PM »
You should know how to write these expressions, they are the most basic thing in the equilibrium calculation. They are not given - but you can write them just after seeing reaction equation.
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Offline cho_reunited

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Re: Equilibrium - 4 questions
« Reply #6 on: October 09, 2011, 08:29:02 PM »
I do know how to write expressions...but that doesn't help me here.

Offline Borek

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Re: Equilibrium - 4 questions
« Reply #7 on: October 10, 2011, 04:06:02 AM »
Try to multiply Kforward*Kreverse. What do you get?
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Offline Vidya

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Re: Equilibrium - 4 questions
« Reply #8 on: October 10, 2011, 06:16:01 AM »
K  reverse  reaction =1/ K forward

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