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Topic: fluorenone to fluorenol reduction  (Read 6493 times)

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Offline elduderino

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fluorenone to fluorenol reduction
« on: October 10, 2011, 06:52:20 PM »
Hello,

I have this question on a pre lab that I am stuck on..

How many grams of fluorenone can 0.53 moles of sodium borohydride reduce?

That is all of the info that is gives. Is that enough to solve it?  Confused??
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Offline Honclbrif

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Re: fluorenone to fluorenol reduction
« Reply #1 on: October 10, 2011, 07:01:41 PM »
http://www.chemicalforums.com/index.php?topic=51733.0

How many moles of hydride does borohydride produce?

How many moles of hydride does fluorenone react with?

From there you should be able to work out the stoichiometry.
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Offline elduderino

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Re: fluorenone to fluorenol reduction
« Reply #2 on: October 10, 2011, 07:29:48 PM »
So BH4 has 4 and fluorenone will react with one?



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Offline elduderino

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Re: fluorenone to fluorenol reduction
« Reply #3 on: October 10, 2011, 07:40:58 PM »
so I did...

1 NaBH4 = 4 Fnone

0.53 x 4 = 2.12

2.12 x 180.192 (1 mol fnone) = 382.01 g

look right??
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Offline Honclbrif

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Re: fluorenone to fluorenol reduction
« Reply #4 on: October 10, 2011, 07:51:37 PM »
Sounds about right. 4 fluorenone to 1 borohydride.
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