November 13, 2024, 01:28:19 AM
Forum Rules: Read This Before Posting


« previous next »
Pages: [1]   Go Down

Topic: Product of propanal and NaOMe + MeOH  (Read 3706 times)

0 Members and 1 Guest are viewing this topic.

Offline andorrak

  • New Member
  • **
  • Posts: 5
  • Mole Snacks: +0/-0
Product of propanal and NaOMe + MeOH
« on: October 13, 2011, 10:47:32 PM »
I am slightly confused. I know when I add a strong base and h20 the oxygen will lose the hydrogen.

But in the mechanism in the subject, of propanal and NaOMe and MeOH. Can the MeOH protonate the Oxygen?

Giving 1-Propanol?
Logged

Offline Doc Oc

  • Chemist
  • Full Member
  • *
  • Posts: 564
  • Mole Snacks: +48/-12
Re: Product of propanal and NaOMe + MeOH
« Reply #1 on: October 13, 2011, 11:11:17 PM »
Look up aldol reactions.
Logged

Offline andorrak

  • New Member
  • **
  • Posts: 5
  • Mole Snacks: +0/-0
Re: Product of propanal and NaOMe + MeOH
« Reply #2 on: October 14, 2011, 12:15:41 AM »
Well the answer didn't really help me at all. But I found it myself anyways. And i guess thats better for me :P
Logged

Offline opsomath

  • Chemist
  • Full Member
  • *
  • Posts: 472
  • Mole Snacks: +50/-8
Re: Product of propanal and NaOMe + MeOH
« Reply #3 on: October 14, 2011, 09:34:50 AM »
Why didn't the answer help you? Did you not do what it said?
Logged

Offline Nosterius

  • Regular Member
  • ***
  • Posts: 66
  • Mole Snacks: +5/-0
Re: Product of propanal and NaOMe + MeOH
« Reply #4 on: October 14, 2011, 11:10:56 AM »
Andorrak: From your first post, you seem to think that propanal will be reduced to 1-propanol. What would be your reductant then?

Personally, I would have followed Doc Oc's suggestion of looking up the aldol reaction. He really gave a great advice.
Logged
Pages: [1]   Go Up
« previous next »
Sponsored Links