What is pH if system has 500 ml of.1 M HCL and Concentration of OH ?
How I solve it
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HCL = H30 because 100% ionization
Ph = -log[.1] = ph
Take the ph and subtract it from 14 to give me my pOH
Than take = [OH] = 10^-pOH
Is this correct way ?
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Topic: Find PH and OH (Read 1739 times)