hello, this problem is tough, and I did everything very carefully but it doesn't turn out correctly.
Iron (II) reacts with the dichromate ion in acidic solution rapidly and completely according to the following reaction:
14H+ (aq) + 6Fe2+ (aq) + Cr2O72- (aq) ===> 6Fe3+ (aq) + 2Cr3+ (aq) + 7H2O (l). How many milliliters of 0.0124 M Cr2O72- are required to react with 0.742g of Fe(NH4)26H2O, a source of Fe2+ ion?
At one point I got 25.4 mL, and at another point I got 152.6 mL.