a. 2-propanol (60.10g/mol) has a density of 0.785 g/ml. Calculate the mg in 825 uLs of 2-propanol.; Calculate the moles of 2-propanol in 825 uLs.
825 uL = .825 ml
0.785 g/ml=mass/(.825 ml)
(.825 ml)0.785 g/ml= .647625 g
.647625 g ×1000=647.625 mg of 2"-propanol"
The number is OK, but the number of significant figures is inappropriate.
You were also asked to find the moles, which you've not done.
b. A dehydration reaction calls for 125 mmoles of cyclohexanol. The density of cyclohexanol is 0.948. Calculate the volume in mLs needed for the experiment.
0.125 moles ((100.158 g cyclohexanol)/(1 mol)) ((1 ml)/(0.948g cyclohexanol))=13.206 ml
Again, check significant figures, otherwise OK.
c. The same reaction produces 0.495 grams of cyclohexene. Calculate the moles of cyclohexene produced.
0.495 g ((1 mol)/(82.143g cyclohexene))=0.00602 moles of cyclohexene
Fine.
Assume a 1:1 molar ratio of reactant to product in this reaction. What is the theoretical yield of the product, cyclohexene, in moles? What is the percent yield of cyclohexene?
It means that 1 mol of cyclohexanol can produce 1 mol of cyclohexene.
Theoretical yield is the maximum amount of product (cyclohexene) that can theoretically be produced from the starting material (cyclohexanol).
The actual percent yield an expression of the actual amount of material you get experimentally as a percentage of the theoretical yield. E.g. if the theoretical yield is 4 g, then I do the experiment and get 3 g, my yield is 75% (because 3 is 75% of 4, or (3/4)*100 = 75).