About the octet rule, atom tend to gain or lose electrons to have 8 electrons in the valence shell. However, in the periodic table, some elements have the big atomic number ( eq: Ge, Pb....etc ) They have a lot of shells in their atom. So, with the octet rule, as I understand, we can write ( Ge: 32 = 2)8)8)8)6 ).
But, in the electron configuration, we write ( Ge : first shell: 2e, second shell 8e ( 2s^2 2p^6), third shell 18e ( 3s^2 3p^6 3d^10 ) and so on. It means that with the third shell also have 18e. Is this broke the octet rule?
I tried to look up the answer but it still mystery to me. Thank you for your help.