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Topic: Termochemistry  (Read 2203 times)

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Offline Rutherford

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Termochemistry
« on: January 31, 2012, 12:07:30 PM »
When you dissolve a substance in water and the temperature decreases, why is dH>o? When analysing the formulas when the temperature decreases:t2<t1---t2-t1<o---Q<o---dH<o.
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Offline Pradeep

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Re: Termochemistry
« Reply #1 on: January 31, 2012, 12:14:02 PM »
dH > 0 for the dissolution process. At constant pressure -dQ = dH
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Offline Rutherford

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Re: Termochemistry
« Reply #2 on: January 31, 2012, 12:51:10 PM »
I've never heard that at constant pressure in dissolution process -dQ = dH. That makes it clear. Thanks a lot.
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