Perfect.
And on a better note, I think I actually figured it out. Let me know what you think:
I took the derivative in terms of $$ \frac{d^{2}y}{dx^{2}} $$ and $$ \frac{d^{2}y}{dt^{2}} $$
Then setting them equal to each other using the this definition:
$$ \frac{d^{2}y}{dx^{2}} = \frac{1}{v^{2}} \frac{d^{2}y}{dt^{2}} $$
and solving showing that they are equal, therefore saying that the wavelength is lambda.
I actually worded the original question quite badly. I was putting it in my own words, but I had to prove that lambda was the wavelength for the equation given, that the frequency was mu=v/lambda, and that the velocity goes to the right. I figured out the other parts also (I hope), but won't worry about it too much.