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Topic: AP Chem Gas Problem  (Read 4801 times)

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konkani1kaiser

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AP Chem Gas Problem
« on: November 01, 2005, 08:31:40 PM »
Hey i just cant get this question, some help please.

The density of a liquid nitrogen is .808g/mL at 77K. What volume of nitrogen gas at stp, must be liqufied to make 10.0L of liquid nitrogen?

I tried finding moles nitrogen for some reason, but my answer was unhelpful, and i dont the the ideal will help here. Please can someone help.
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Offline mike

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Re:AP Chem Gas Problem
« Reply #1 on: November 01, 2005, 08:46:42 PM »
If its density is 0.808g.mL-1 --> 808g.L-1  in 10 litres ----> 8080g

PV=nRT

--> V = mRT/MP

you know: m, R, T, M, and P :)
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konkani1kaiser

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Re:AP Chem Gas Problem
« Reply #2 on: November 01, 2005, 09:05:02 PM »
what would M be, also i get V = 3648.5L, not quite right?
« Last Edit: November 01, 2005, 09:08:03 PM by konkani1kaiser »
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Offline mike

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Re:AP Chem Gas Problem
« Reply #3 on: November 01, 2005, 09:13:47 PM »
V = mRT/MP

m = 8080g
R = 0.0821L.atm.K-1.mol-1
T = 273K
M = 28g.mol-1
P = 1atm

V = 6468L
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There is no science without fancy, and no art without facts.
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