[Chrataxe]

Ok...we were told that they don't teach this reaction in entry level organic anymore but they used to.  When our teacher gave us our handout, it was on there.  He said if we could figure it out, we would get extra credit.  I'm having trouble finding the reaction....

CH3-CH2-CH=CH2 + MnO4(-)--->?

I've seen reactions dealing with acidic and basic conditions....but, that is all we are given.  Any ideas?

[Borek]

CH3-CH2-CH=CH2 + MnO4(-)--->?
Any ideas?

Best idea always: Google double bond and permanganate.

[movies]

Another idea is to think about any other reagents that you know that have a similar structure to MnO₄- and think about the reactivity of those reagents.

[fran008]

The reagent KMnO4 (conc and hot) is used to oxidise alkenes to determine position of C=C bond

CH3-CH2-CH=CH2 + MnO4(-)--->CH3-CH2CHO + CH2O

[Borek]

->CH3-CH2CHO + CH2O

Are you sure the reaction stops here?

[Alberto_Kravina]

->CH3-CH2CHO + CH2O

Are you sure the reaction stops here?

I think i t reacts so:

H₃C-H₂-CHO + H₂CO ------> H₃C-(CH₂)₂-COOH

I'm not totally sure about this...an aldehyde reacts with another to form an acid

[Mitch]

The reaction turns an alkene into a diol if you work it up in aqueous solution.

[Albert]

CH3-CH2-CH=CH2 + MnO4(-)--->?

Yes, the product is a diol: CH3-CH2-CHOH-CH2OH...and MnO2

These are the conditions: T=0°C, pH = 7, solvent: pure water.

Please, pay attention: the OH groups are CIS.

[HP]

The formed diol could ferder oxidize to corresponding propionate salt  CH3-CH2-COO:-K+ and HCOO-:K+ especially in heating. I am not sure if potassium formiate could ferder oxidise to CO2.

[Mitch]

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