[johnsholto]

Could someone explain to me how I can calculate the ratio of partial pressures, specifically in the Boudouard reaction?

C + CO2 -> 2CO (p=100kpa)

Kp=1

Feedback on this, please:

-->
100kpa=p(co)^2+p(co2)

-->
Kp=1=p(co)^2/p(co2)
P(co2)=p(co)^2

-->
100kpa=p(co)^2+p(co)^2
√50kpa=p(co)^2
50kpa=p(co2)

-->
p(co):p(co2)=√50:50

[PIQgoogleme]

By Dalton's law, we know the total pressure equals the sum of the partial pressures.

100kpa = p(CO) + p(CO2) --> p(CO2) = 100kpa - p(CO)

Using the equilibrium expression:

P(CO)^2/P(CO2) = 1 --> P(CO)^2 = P(CO2)

Substituting gives us:
P(CO)^2 = 100kpa - p(CO) --> P(CO)^2 + p(CO) - 100kpa = 0

since P(CO) clearly must be positive, P(CO) = 9.51kpa and P(CO2) =90.5 kpa