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Redox reaction
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Topic: Redox reaction (Read 2329 times)
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Rutherford
Sr. Member
Posts: 1868
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Redox reaction
«
on:
March 06, 2012, 10:32:37 AM »
I don't know how to balance this reaction:
GeS
2
*4Ag
2
S+K2CO
3
+KNO
3
-->K
2
GeO
3
+K
2
SO
4
+KNO
2
+Ag+CO
2
S, Ag and C are changing their oxidation states, so how to write the oxidation and reduction half-reactions?
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AWK
Retired Staff
Sr. Member
Posts: 7978
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Re: Redox reaction
«
Reply #1 on:
March 06, 2012, 11:19:30 AM »
Calculate net number of removed electrons for the whole molecule
GeS
2
*4Ag
2
S = Ag
8
GeS
6
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AWK
Rutherford
Sr. Member
Posts: 1868
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Re: Redox reaction
«
Reply #2 on:
March 06, 2012, 11:32:28 AM »
3S
-2
are converted to 3 S
+6
8Ag
+
are converted to 8Ag
0
3*(-2)+8*1=2
3*6+8*0=18
18-2=16e
-
16e
-
are deducted?
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Rutherford
Sr. Member
Posts: 1868
Mole Snacks: +60/-29
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Re: Redox reaction
«
Reply #3 on:
March 07, 2012, 08:15:18 AM »
Oh, I made a mistake. There are 6S atoms so the electron change is -40e
-
and for the nitrate and nitrite is +2e
-
and when I multyply this by 20 the equation can be easily solved. Thanks very much!
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Redox reaction