[Medic1992]

I want to calculate the percentage radioactivity due to pertechnetate ions in an sample.

A drop of the solution was placed on the chromatographic paper on the origin line. After the strip was developed and dried, it was then cut into two parts ( Part A is smaller than Part B). 2 Readings were done, and a duplicate was also done. Any impurities in the sodium pertechnetate solution remained at the origin. RF value for the pertechnetate ion is 0.6.

 Results for Duplicate 1:

Reading 1: Part A - 830 Part B - 11,800
 Reading 2: Part A - 790 Part B - 11,750

 For Duplicate 2:

 Reading 1: Part A- 940 Part B - 17,800
 Reading 2: Part A - 960 Part B - 17,700

 BP test criteria:

Radioactivity (Mo-99) = 0.058%
Radioactivity due to other radionuclidic impurities = 0.007%

[Medic1992]

Anyone?