35.0 mL of a 0.20M hydroxylamine (HONH2) is titrated with 0.10 M hydrochloric acid.
HONH2: Kb = 1.1 x 10^-8
pOH = PKb + log([HB+]/[ B])
I have to use this info/calculate to make a titration curve. So I need to find halfway point, when pOH=pKb, equivalence, etc. to sketch one.
Please explain your steps!! I think equiv point is 70 ml and the halfway is 35.0 mL of HCL. I just need someone to explain how to get that and any other calculations.