This is my calculation problem for my lab: Calculate the grams of NaOH needed to prepare 100. ml of 0.50 M solution.
M = (# of moles in solute) / .1 L
# of moles in solute = .05 mol NaOH
.05 mol NaOH * (40 g NaOH / 1 mol NaOH) =
2 g NaOHAm I on the right track?
Thank you in advance for any advice!