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Solubility Product Constant (Basic)
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Topic: Solubility Product Constant (Basic) (Read 2241 times)
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nannon27131
Very New Member
Posts: 2
Mole Snacks: +0/-0
Solubility Product Constant (Basic)
«
on:
April 08, 2012, 09:35:28 PM »
The question: Find the Ksp of Silver Acetate.
It is based on a lab conducted where copper metal is made to react with 0.1L silver acetate solution (saturated).
The 2 relavent equations are: Cu + 2Ag
+
--> Cu
2+
+ 2Ag and
C
2
H
3
O
2
Ag <=> C
2
H
3
O
2
-
+ Ag
+
The mols of Cu reacted was given (9.44 x 10
-4
)and I used that to find concentration of Ag
+
using the first equation, equivalent mol ratios and the formula c=n/v (v=0.1L). I got 0.0189 M.
****I realize Ksp = [Ag
+
][C2H3O2
-
] but how do I find molar [C2H3O2]!?
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Foobarz
Regular Member
Posts: 73
Mole Snacks: +0/-2
Re: Solubility Product Constant (Basic)
«
Reply #1 on:
April 08, 2012, 11:42:21 PM »
Its the same:
From your equation : C2H3O2Ag <=> C2H3O2- + Ag+
We see that [Ag+] and [C2H3O2-] are equivalent at equilibrium, since it is one to one molar ratio.
So in your case (if your value of [Ag+] is correct), Ksp = 0.0189^2, Ksp=3.57*10^-4.
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Solubility Product Constant (Basic)