Explain the following reactivity order during a Lucas test:
3-methyl-1-buten-3-ol > 2-methyl-1-buten-3-ol > 3-methylbutan-2-ol > 3-methylbutan-1-ol
-I know that 3° alcohols react very fast with the Lucas reagent, secondary reacts slowly, and primary tend not to react at all at room temperature.
I am not sure how to account for the order above because I'm getting:
3-methyl-1-buten-3-ol-primary alcohol
2-methyl-1-buten-3-ol -
3-methylbutan-2-ol –Secondary alcohol
3-methylbutan-1-ol-primary alcohol
Any thoughts?