[luketapis]

Hi
I have a question about dⁿconfiguration for this molecule:
[Ir(CO)Cl(PPh₃)₂]
ligands charges are:
CO: n
Cl : -1
PPh₃: n

so Ir(I)
Ir configuration is: 3d⁷ 4s²

If we take one electron away from Ir, we letf with d⁷ or d⁸ ?

[Schrödinger]

Ir configuration is: 3d⁷ 4s²

[Xe] 4f¹⁴ 5d⁷ 6s²
And I guess you should be left with d⁷ s¹

[Dan]

The ground state of Ir⁺ is s¹d⁷

luketapis: Note that atomic orbitals do not provide a good representation of the electronic structure of transition metal complexes, you should use molecular orbitals (ligand field theory).

[cheese (MSW)]

In the gas phase phase Ir^+ may be [Xe] 5d^7 6s^1, but just as likely it could be [Xe] 5d^8.
In cmplxs however TM are always referred to by their d e⁻  cnfig so trans-IrCl(CO)(PPh3)2
(Ir(I)) is a d^8 cmpd and as such is sq planar.  It is known as Vaska's cmpd.

[luketapis]

that what I thought Cheese
I would go for d⁸ as well.
Thx