[NathanielZhu]

What would Qc be if the volume of the container decreased by a factor of 4.284 for the following reaction?
PH3BCl3(s) <--> PH3(g) + BCl3(g)      KC = 0.001870
at 353.0 K
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I tried to look at the formula:
Kp = Kc(RT)^(delta n)
For (RT)^(delta n), which I assume I solve normally, I just plug in numbers for it so I get,
(RT)^(delta n) = (0.0821)(353)^(2)

So, the only thing I need to compare is Kc and Kp.
Since the container is decreasing, pressure is increasing by 4.284, so
I multiply Kc by 4.284
Kp = ((4.284)(0.001870))((0.0821)(353)^(2))

So I get Kp, and I get the answer wrong.