[Ari Ben Canaan]

Part (b) is where I'm having an issue.

So the cathode reaction has a reduction potential of -0.83 V

The anode reaction (in the case of the formation of Oxygen) has a reduction potential = +1.23V

So E_reduced - E_oxidised = -0.83-1.23 = -2.06 V

However, the mark scheme gives a positive value....

What have I done wrong ?