Topic: AgCl + ??? --> AgNO3 (Read 7241 times)

rbss · « **on:** May 01, 2012, 05:50:26 PM »

I had a precipitation lab and AgCl was left. How would i go about getting it back into AgNO3???

AWK · « **Reply #1 on:** May 01, 2012, 05:53:51 PM »

Reduction to metal followed by dissolution in nitric acid.

rbss · « **Reply #2 on:** May 01, 2012, 06:32:51 PM »

I know this might be dumb of me to ask but how would I do that. ie what would to that, Cu?

AWK · « **Reply #3 on:** May 03, 2012, 11:11:29 AM »

I know this might be dumb of me to ask but how would I do that. ie what would to that, Cu?

Zinc or iron are cheaper.

rbss · « **Reply #4 on:** May 03, 2012, 05:52:34 PM »

What about:
AgCl + NH4Oh = AgOH + NH4Cl
AgOH = Ag2O
Ag2O is a precipitate, so filter out
Then: Ag20 + HNO3 = AgNO3 + H2O

Hunter2 · « **Reply #5 on:** May 04, 2012, 12:39:21 AM »

This is difficult to do, because normaly silver get a complex with ammonia.

Ag⁺ + 2 NH₃ => Ag[NH₃]₂⁺

Better is to use NaOH for that.

AWK · « **Reply #6 on:** May 04, 2012, 12:58:11 AM »

This is difficult to do, because normaly silver get a complex with ammonia.

Ag⁺ + 2 NH₃ => Ag[NH₃]₂⁺

Better is to use NaOH for that.

Mor ammonia or NaOH itself will not work but reduction of Ag⁺ in ammonia complex is much faster.

rbss · « **Reply #7 on:** May 04, 2012, 01:48:17 AM »

So it would be better to go with:
AgCl + NaOH = Ag2O + NaCl + H20;
Ag20 + HNO3 = AgNO3 + H20?

AWK · « **Reply #8 on:** May 04, 2012, 02:48:49 AM »

AgCl will not react with NaOH (unless heating over melting point of NaOH).
Reduce ammonia complex with metal, then dissolve Ag in nitric acid.