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Topic: E = mc2  (Read 1737 times)

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Offline NathanielZhu

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E = mc2
« on: May 04, 2012, 08:30:13 PM »
How kJ are released to form one mole of 204Pb from protons and neutrons if the atom has a mass of 203.973020 amu?
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I think I'm supposed to use E = mc2
I just plug in E = (.203973020kg)(3 X 10^8)^2.
I get a wrong answer.
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Offline Borek

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Re: E = mc2
« Reply #1 on: May 05, 2012, 02:36:08 AM »
What is a mass deficit for 204Pb?
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