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Topic: molar solubility  (Read 4989 times)

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Offline hannah2329

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molar solubility
« on: May 13, 2012, 06:00:08 PM »
Calculate the molar solubility of Cr(OH)3 in 0.54 M NaOH. Kf for Cr(OH)4- is 8x10^29 please help with this problem! ive tried everything!
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Offline JustinCh3m

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Re: molar solubility
« Reply #1 on: May 14, 2012, 12:00:05 AM »
Kf = [Cr3+][3(OH)]^3

Kf = (x) (3x)^3

this should get you started...
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Offline hannah2329

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Re: molar solubility
« Reply #2 on: May 14, 2012, 09:39:11 AM »
so do I plug the .54 in there and make it 8x10^29=(x)(.54-3x)^3??
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Offline AWK

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Re: molar solubility
« Reply #3 on: May 14, 2012, 02:21:04 PM »
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