[Twickel]

Hi
I am having trouble understanding how to write rate laws.

O₃ + Cl   ClO + O₂
ClO + O --> Cl + O₂

Overall O₃ + O   2O₂

why is it d[ClO]/dt= k [O₃][Cl]

Thanks

[Borek]

Think about stoichiometry.

[Twickel]

I actually want to know why we use those reactants products in the rate law.

II thought A+B --> C then its k[a]/dt = k[a]

[Borek]

I am not sure where the problem is, as what you wrote doesn't make much sense to me. You can put it any way you want, as concentration changes are related to each other by the reaction stoichiometry.

C + D  E

[tex]\frac{d[C]}{dt}=\frac{d[D]}{dt}=-\frac{d[E]}{dt}[/tex]

Or

F + 2G  3H

[tex]\frac{d[F]}{dt}=\frac{d[G]}{2dt}=-\frac{d[H]}{3dt}[/tex]

(unless I am having a massive brain fart)

[Twickel]

Sorry, maybe I was not being clear ( as is usually the case)

Why in this specific example, have they put the ClO in the reaction rate and not O2?

Also shouldnt it be -d[ClO]/dt because the ClO is a product?

What does the rate law tell me about the reaction?

[Twickel]

Is it because the first equation is the rate limiting step, so we use that as the elementary reaction so its simple A+ B ---> C+D rate law with regards to Clo is d[Clo]/dt=k[O3][Cl]?

I thought we should not put ClO in the rate of reaction because we do not observe it, it is a reaction intermediate.

[Borek]

[tex]\frac{d[ClO]}{dt} = \frac{d[O_2]}{dt}[/tex]

You can use whichever you want, perhaps they had a reason to do it this way, no idea.

You are most likely about the sign thing.