[beruniy]

During separation of the mixture of alcanes and unknown matter (X) the following data were obtained:
Retention  time:
ethane - 4 minutes
propane - 8 minutes
Corrected retention time for X = 5,2 min
Kovats index I = 246
Separation factor (X and propane) = 1.
Henry coefficients for X and pentane 20.1 and 2.8, respectively.

But the peak was damaged by H₂SO₄
I need to recover it. I know only its intensity = 75. I need to know its width and 1/2 of width.

From Kovats index I can calculate retention time for X, it is 5,5 minutes. Then I calculate the "dead" time.
t₀ = 5,5 - 5,2 = 0,3 min.
Knowing that intensity is the function of time (I = f(t)) I can suppose that the peak is symmetric and I can consider it as isosceles triangle.

But, how is it possible to associate Henry coefficients with retention times?