Hi again,
I'm having some difficulty with a question in my textbook regarding the actual, theoretical, and percent yield of a reaction.
P
4(s) + 6Cl
2(g)
4PCl
3(l)
The question: What is the percent yield if the reaction of 25.0 g P
4 and 91.5 g Cl
2 produces 104 g PCl
3?
My attempt:
Well obviously the actual yield of PCl
3 in this case is 104 g, but my issue is with calculating the theoretical yield. You could use the mole ratio to discover the theoretical yield per
mole of PCl
4, but I'm not sure how that would help you in comparing with the actual yield.
So my next guess was to convert the following:
25.0 g P
4 mol P
4 mol PCl
3 g PCl
3Which turned out to be 111 g PCl
3- so right now it looks alright to me, the theoretical being larger than the actual yield. My logic was using the amount of one of the reactants to find the amount of product- aka the theoretical method.
But then I tried converting the other reactant, 91.5 g Cl
2, to g PCl
3 using the same pathway:
91.5 g Cl
2 mol Cl
2 mol PCl
3 g PCl
3But this resulted in 118 g PCl
3. Here is where I'm stumped.
Am I supposed to use a weighted average of the amount of product or something? Right now it seems I have
two theoretical yields- 111 g and 118 g. All the exercises prior to this only dealt with yield per mole of product so I really don't know where to go from here.
Thanks again guys