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Topic: Calculation Question  (Read 3068 times)

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Offline Celebi22

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Calculation Question
« on: July 29, 2012, 02:06:41 PM »
Hello, I'm very unsure how to do this type of calculation, so could you show me your method in your answer?

Say the loading of a reducing agent was 5mmol/g, how much of this reducing agent would be needed to produce 700mg of compound 1 (RMM of 250g/mol) to compound 2 (RMM of 260g/mol) and the percentage yield going from 1 to 2 is 90%

Thankyou

Offline Dan

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Re: Calculation Question
« Reply #1 on: July 30, 2012, 02:49:55 AM »
The phrasing of the question is confusing. Is this translated?

Quote
to produce 700mg of compound 1 (RMM of 250g/mol) to compound 2 (RMM of 260g/mol)

This doesn't make sense, does it mean:

to reduce 700 mg of compound 1 to compound  2
or
to produce 700 mg of compound 2 from compound 1
or something else?

I suspect it is the second option, i.e. the reaction is 1 :rarrow: 2, the yield is 90% and you need 700 mg of the product 2 - is that correct?

If so:

Hint: How many mmol of 2 are produced? Based on a 90% yield, how many mmol of 1 do you need to produce that?
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Offline Celebi22

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Re: Calculation Question
« Reply #2 on: July 30, 2012, 05:17:40 AM »
Hi, thanks for replying. No it's not translated, it's just phrased quite confusingly on my sheet.
700mg of compound 1 is being reduced and compound 2 is produced as a result in 90% yield, if that makes sense?

Offline AWK

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Re: Calculation Question
« Reply #3 on: July 30, 2012, 05:36:09 AM »
Hi, thanks for replying. No it's not translated, it's just phrased quite confusingly on my sheet.
700mg of compound 1 is being reduced and compound 2 is produced as a result in 90% yield, if that makes sense?
This make sense if you know formulas of compounds 1 and 2. In that case this concerns calculations for reaction with known yield eg. acetone (CH3COCH3) is reduced to isopropyl alcohol CH3CHOHCH3) with 90 % yield - you can calculate the mass of isopropyl alcohol obtained in this reaction.
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Offline Celebi22

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Re: Calculation Question
« Reply #4 on: July 30, 2012, 06:16:11 AM »
Thanks, yes I have the formulas. I hope this doesn't sound silly, but how would I calculate the mass using your example?

Offline AWK

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