[Rutherford]

On passing ethanol over a catalyst at 400 K, a dehydration reaction occurs resulting in the formation of ethylene:
C₂H₅OH(g) C₂H₄(g) + H₂O(g)
At the above temperature and p⁰ = 101.325 kPa, the conversion of ethyl alcohol is 90.6 mol %. Calculate K_p and K_c of the reaction under given conditions and at the above temperature.

1.For K_p I got the result 4.58*p⁰=464kPa, I need someone to check if this is correct.

2.For K_c, to calculate the volume I need to assume that the process is isothermic and isobaric. It is isothermic because of "and at the above temperature", but how do I know that it is isobaric?

[curiouscat]

I get 8.73*P0 for Part 1


Maybe I messed up...

[Rutherford]

I did it through the molar shares i.e. partial pressures. In the answer it is without p⁰, only 4.56 and I can't see where the p⁰ gets reduced.

[outman]

I did it through the molar shares i.e. partial pressures. In the answer it is without p⁰, only 4.56 and I can't see where the p⁰ gets reduced.

maybe the answer was wrong.

[Rutherford]

Okay, then I believe that you got the same as I got.