[luketapis]

Hi everybody
I had an experiment, the first part is like follow: Pipette 25.00 cm^3 of the solution of vanadium(V) sulfate into a conical flask containing 20 cm^3 dilute sulfuric acid and add a few crystals of sodium sulfite:
SO3^2–(aq)   +   2H + (aq)    H₂O(l)   +   SO₂ (g)
Than I have to write balanced equation for reaction of V(V) with SO₂.
I am also told that vanadium(V) sulfate formula is: [(VO₂)₂SO₄],
so according to my data it should be:
[(VO₂)₂SO₄] + H₂SO₄+ Na₂SO₃

Am I right?
What to do next?

[Borek]

Sulfite gets oxidized to sulfate.

[luketapis]

so you sugesting that
SO₃^2- ->SO₄^2-
How do you know it? And what happens to [(VO₂)₂SO₄] ?

[luketapis]

Any hints?

[Borek]

V(V) is the oxidizer here and gets reduced, no doubt about it. But to be honest I am not sure how far - you may need to consult standard potential tables.